Question : What should be changed to make this code work under PHP4?

Hi Experts,

I've got this functionality that works under PHP5 but not under PHP4. I don't have enough nowlige to know what should be changed.

Please help me to get this working under PHP4

Thanks,
Code Snippet:
-------------end of sort.php--------------------- -------------sort_db.php--------------- conn = mysql_connect($this->host, $this->user, $this->pass); mysql_select_db($this->dbname,$this->conn); } public function getList() { $sql = "SELECT * FROM nieuws ORDER BY volgorde ASC, nieuwsID desc LIMIT 15"; $recordSet = mysql_query($sql,$this->conn); $results = array(); while($row = mysql_fetch_assoc($recordSet)) { $results[] = $row; } return $results; } public function updateList($orderArray) { $volgorde = 40; foreach($orderArray as $nieuwsID) { $nieuwsID = (int) $nieuwsID; $sql = "UPDATE nieuws SET volgorde={$volgorde} WHERE nieuwsID={$nieuwsID}"; $recordSet = mysql_query($sql,$this->conn); $volgorde++; } } } ?> --------------------end of sort_db.php ------------------sort_ajax.php-------------- updateList($_POST['listContainer']); ?> ------------------end of sort_ajax.php--------------------- Open in New Window Select All Please take a moment to respond Did this comment work for you? Yes Partially No Was the comment complete? Yes Partially No Was the comment easy to understand? Yes Partially No Overall, how would you rate this comment? Excellent Good Average Submit | Cancel 15/05/09 09:53 PM, ID: 24399622 Was this comment helpful? Yes No Steynsk:There is a large difference between the both versions. The production is Version 4.4.7 The test is PHP Version 5.2.5 And a lot of configuration differences. What should I look for? Please take a moment to respond Did this solution work for you? Yes Partially No Was the solution complete? Yes Partially No Was the solution easy to understand? Yes Partially No Overall, how would you rate this solution? Excellent Good Average Submit | Cancel 15/05/09 09:58 PM, ID: 24399662 Rank: Sage Was this solution helpful? Yes No Ray_Paseur:PHP 4 and PHP 5 handle Object oriented programming VERY differently. I am not even sure that PHP 4 can use the "protected" type of vars. When are you planning to upgrade the production server to PHP5 (or php6)? PHP4 is kind of dead now. A Author Comments: thanks Not what you're looking for? Ask an Expert. Please take a moment to respond Did this comment work for you? Yes Partially No Was the comment complete? Yes Partially No Was the comment easy to understand? Yes Partially No Overall, how would you rate this comment? Excellent Good Average Submit | Cancel 15/05/09 10:57 PM, ID: 24400051 Rank: Master Was this comment helpful? Yes No Hube02:PHP4 does not handle classes the same way as PHP5. Basically you cannot use any of the public/private/protected stuff, this is where your error lies. You will either need to remove it all or upgrade the server to PHP5. This is the main reason that I'm still not using the new features of PHP5 and must always code so that my work will run on PHP4. I never know what the environment will be. Add to KnowledgeBase Stop Monitoring Share It! Printer Friendly Add Bookmark This question already has been closed and points assigned. Post additional comments only if you want to clarify or comment on the solution. You can also ask a related question. Plain Text | Rich Text Comment: Attach Code Snippet Copy and paste your code into the text area below. Your formatting will be preserved and your code syntax will be highlighted, when possible. Code Snippet: [x] Allowed Extensions Experts Exchange accepts the following types of files: bmp doc docx gif jpeg jpg log mdb pdf png txt xls xlsx zip Attach File Uploaded files: [x] Add New Email To make changes to your list of email addresses and groups, go to your Notification Preferences. You will then be asked to verify any new email addresses before Experts Exchange will allow you to associate them with a question. 20081217-EE-VQP-LI-5 / EE_QW_3_20080625About Us| Contact Us| Member Agreement| Internet Rank| Privacy Policy| Site Map © Copyright Experts Exchange LLC 1996 - 2009. All rights reserved. 
1:
2:
3:
4:
5:
6:
7:
8:
9:
10:
11:
12:
13:
14:
15:
16:
17:
18:
19:
20:
21:
22:
23:
24:
25:
26:
27:
28:
29:
30:
31:
32:
33:
34:
35:
36:
37:
38:
39:
40:
41:
42:
43:
44:
45:
46:
47:
48:
49:
50:
51:
52:
53:
54:
55:
56:
57:
58:
59:
60:
61:
62:
63:
64:
65:
66:
67:
68:
69:
70:
71:
72:
73:
74:
75:
76:
77:
78:
79:
80:
81:
82:
83:
84:
85:
86:
87:
88:
89:
90:
91:
92:
93:
94:
95:
96:
97:
98:
99:
100:
101:
102:
103:
104:
105:
106:
107:
108:
109:
110:
111:
112:
113:
114:
115:
116:
117:
118:
119:
120:
121:
122:
123:
124:
125:
126:
127:
128:
129:
130:
131:
132:
133:
134:
135:
136:
137:
138:
139:
140:
141:
142:
143:
144:
145:
146:
147:
148:
149:
150:
151:
152:
153:
154:
155:
156:
157:
158:
159:
160:
161:
162:
163:
164:
165:
166:
167:
168:
169:
170:
171:
172:
173:
174:
175:
176:
177:
178:
179:
180:
181:
182:
183:
184:
185:
186:
187:
188:
189:
190:
191:
192:
193:
194:
195:
196:
197:
198:
199:
200:
201:
202:
203:
204:

----sort.php---------
getList();
?>



	Zet de artikelen op volgorde.
	
	
	



Sorteren van nieuwsitems

Sleep de onderstaande titels in de gewenste volgorde. LET OP dit is direct ook de
volgorde waarop de titels worden getoond op de site.

Bovendien worden uit de onderstaande berichten slechts de bovenste 10 op de website getoond.
Open in New Window Select All

Answer : What should be changed to make this code work under PHP4?

Hi Steynsk,

Remove the 'public' (access specifier) before the function defintion for all functions

since public, private, protected are not available in PHP4, its showing error.

1:
2:
3:
4:
5:
6:
7:
8:
9:
10:
11:
12:
13:
14:
15:
16:
17:
18:
19:
20:
21:
22:
23:
24:
25:
26:
27:
28:
29:
30:
31:
32:
33:
34:

conn = mysql_connect($this->host, $this->user, $this->pass);
        mysql_select_db($this->dbname,$this->conn);
    }
   
    function getList() {
        $sql = "SELECT * FROM categories ORDER BY orderid";
        $recordSet = mysql_query($sql,$this->conn);
        $results = array();
        while($row = mysql_fetch_assoc($recordSet)) {
            $results[] = $row;
        }
        return $results;
    }
   
    function updateList($orderArray) {
        $orderid = 1;
        foreach($orderArray as $catid) {
            $catid = (int) $catid;
            $sql = "UPDATE categories SET orderid={$orderid} WHERE catid={$catid}";
            $recordSet = mysql_query($sql,$this->conn);
            $orderid++;
        }
    }
}
?>
Open in New Window Select All
Random Solutions  
 
programming4us programming4us