Question : oracle sql greatest/least question.

Hi..
I'm trying to return in a single row 2 values which are in 2 different rows but the same column


SELECT
c.CUSTOMER_NO,
GREATEST (hw.hardware_no) AS item1,
LEAST (hw.hardware_no) AS item2
FROM
jan.customer c,
jan.hardware hw
WHERE
hw.customer_no = c.customer_no And
c.customer_no = '1234567'



Table view
CUSTOMER NO hardware_no            serial_no
1234567          899999999999999    NULL
1234567          3333333333333       12344
1234567          877777777777777    NULL
1234567          2222222222222       12345


returns
CUSTOMER NO ITEM1 ITEM2
1234567 899999999999999 899999999999999
1234567 333333333333333 333333333333333
1234567 877777777777777 877777777777777
1234567 222222222222222 222222222222222


Where what I would want is...
CUSTOMER NO ITEM1           ITEM2
1234567     899999999999999 333333333333333
1234567     877777777777777 222222222222222


item1 is always larger that item2
serial_no which will always be null for item 1,
and is always present for item 2, though I doubt that this is necessary to solve this problem.

Thanks

Answer : oracle sql greatest/least question.

don't use greatest and least,
use max and min instead:

try this:

SELECT
c.CUSTOMER_NO,
max (hw.hardware_no) AS item1,
min(hw.hardware_no) AS item2
FROM
jan.customer c,
jan.hardware hw
WHERE
hw.customer_no = c.customer_no And
c.customer_no = '1234567'
group by c.customer_no;